Calc home
Average Value of a Function (Calculus AB)
This rundown covers the average value of a function over an interval, a key concept in integral calculus.
Definition
The average value of a function $ f(x) $ on the interval $ [a, b] $ is given by:
$$ f_{avg} = \frac{1}{b-a} \int_a^b f(x) , dx
$$
Explanation:
- $ f_{avg} $ represents the average y-value of the function $ f(x) $ over the interval $ [a, b] $ .
- $ \int_a^b f(x) , dx $ represents the definite integral of $ f(x) $ from $ a $ to $ b $ , which geometrically represents the area under the curve of $ f(x) $ between $ x = a $ and $ x = b $ .
- $ b - a $ represents the length of the interval.
Essentially, we are dividing the area under the curve by the length of the interval to find the average height (y-value) of the function.
Intuition
Imagine a rectangle with width $ (b - a) $ whose area is equal to the area under the curve of $ f(x) $ from $ a $ to $ b $ . The height of this rectangle is the average value of the function, $ f_{avg} $ .
Formula Derivation
The average value formula comes from the Mean Value Theorem for Integrals. Mean Value Theorem
The Mean Value Theorem for Integrals states that if $ f(x) $ is continuous on $ [a, b] $ , then there exists a value $ c $ in $ [a, b] $ such that:
$$ \int_a^b f(x) , dx = f(c)(b - a)
$$
Where $ f(c) $ is the value of the function at some point $ c $ in the interval.
To find the average value, we are essentially finding the constant value of the function, lets call it $ f_{avg} $ , that would give the same area under the curve as the original function over the interval $ [a, b] $ .
So,
$$ \int_a^b f(x) , dx = f_{avg}(b - a)
$$
Solving for $ f_{avg} $ , we get:
$$ f_{avg} = \frac{1}{b-a} \int_a^b f(x) , dx $$
Steps to Calculate the Average Value
- Identify the function: Determine the function $ f(x) $ whose average value you need to find.
- Identify the interval: Determine the interval $ [a, b] $ over which you want to find the average value.
- Compute the definite integral: Evaluate the definite integral $ \int_a^b f(x) , dx $ . This might involve using integration techniques like u-substitution.
- Apply the formula: Plug the result of the integral and the interval endpoints into the average value formula: $ f_{avg} = \frac{1}{b-a} \int_a^b f(x) , dx $ .
- Simplify: Simplify the expression to find the average value $ f_{avg} $ .
Examples
Example 1:
Find the average value of $ f(x) = x^2 $ on the interval $ [0, 2] $ .
- Function: $ f(x) = x^2 $
- Interval: $ [0, 2] $
- Definite Integral:
$$ \int_0^2 x^2 , dx = \left[ \frac{x^3}{3} \right]0^2 = \frac{2^3}{3} - \frac{0^3}{3} = \frac{8}{3}
$$ 4. Average Value:
$$ f{avg} = \frac{1}{2-0} \int_0^2 x^2 , dx = \frac{1}{2} \cdot \frac{8}{3} = \frac{4}{3}
$$
Therefore, the average value of $ f(x) = x^2 $ on the interval $ [0, 2] $ is $ \frac{4}{3} $ .
Example 2:
Find the average value of $ f(x) = \sin(x) $ on the interval $ [0, \pi] $ .
- Function: $ f(x) = \sin(x) $
- Interval: $ [0, \pi] $
- Definite Integral:
$$ \int_0^\pi \sin(x) , dx = \left[ -\cos(x) \right]0^\pi = -\cos(\pi) - (-\cos(0)) = -(-1) - (-1) = 1 + 1 = 2
$$ 4. Average Value:
$$ f{avg} = \frac{1}{\pi - 0} \int_0^\pi \sin(x) , dx = \frac{1}{\pi} \cdot 2 = \frac{2}{\pi}
$$
Therefore, the average value of $ f(x) = \sin(x) $ on the interval $ [0, \pi] $ is $ \frac{2}{\pi} $ .
Common Mistakes
- Forgetting the $ \frac{1}{b-a} $ factor: This is a very common mistake. Make sure to divide the definite integral by the length of the interval.
- Incorrectly evaluating the definite integral: Pay close attention to the limits of integration and the antiderivative.
- Mixing up the average value with the average rate of change: The average value is about the y-values of the function, while the average rate of change is about the slope of the function. Average Rate of Change vs Average Value
Applications
The average value of a function has applications in various fields:
- Physics: Finding the average velocity, average acceleration, etc.
- Engineering: Calculating the average power consumption, average temperature, etc.
- Economics: Determining the average cost, average revenue, etc.
Important Integration Techniques
Remember to review your integration techniques, especially u-substitution, as they will be necessary to evaluate the definite integrals required for calculating the average value of a function.