Reaction Quotient

Carson West

Equilibrium

Reaction Quotient (Q) - AP Chemistry Rundown

The reaction quotient, denoted as Q, is a concept closely related to equilibrium. It provides a snapshot of the relative amounts of reactants and products present in a reaction at any given point in time. Comparing Q to the equilibrium constant, K, allows us to predict the direction a reversible reaction will shift to reach equilibrium.

Definition and Calculation

The reaction quotient, Q, is calculated using the same formula as the equilibrium constant, K, but with non-equilibrium concentrations or partial pressures.

Comparing Q and K

The comparison of Q and K is crucial for predicting the direction of a reaction shift.

  1. Q < K: The ratio of products to reactants is less than at equilibrium. The reaction will shift to the right, favoring the formation of more products to reach equilibrium.

  2. Q > K: The ratio of products to reactants is greater than at equilibrium. The reaction will shift to the left, favoring the formation of more reactants to reach equilibrium.

  3. Q = K: The system is at equilibrium. There is no net change in the concentrations of reactants and products. Le Chatelier’s Principle

Applications

Example Problem

Consider the following reaction:

$$ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) $$
At a certain point in time, the partial pressures are: $$ P_{N_2} = 2 \ atm $$ , $$ P_{H_2} = 1 \ atm $$ , and $$ P_{NH_3} = 3 \ atm $$ . The equilibrium constant, $$ K_p $$ , for this reaction at the given temperature is 8.

  1. Calculate Q:

    $$ Q_p = \frac{(P_{NH_3})^2}{(P_{N_2})(P_{H_2})^3} = \frac{(3)^2}{(2)(1)^3} = \frac{9}{2} = 4.5 $$

  2. Compare Q and K:

    $$ Q_p = 4.5 $$ and $$ K_p = 8 $$
    Since $$ Q_p < K_p $$ , the reaction will shift to the right to reach equilibrium, favoring the formation of more ammonia ( $$ NH_3 $$ ). ICE Tables

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